4x^2+7x-5=x^2-9.

Solution for 4x^2+7x-5=x^2-9. equation:

4x^2+7x-5=x^2-9.

We move all terms to the left:

4x^2+7x-5-(x^2-9.)=0

We get rid of parentheses

4x^2-x^2+7x+9.-5=0

We add all the numbers together, and all the variables

3x^2+7x+4=0

a = 3; b = 7; c = +4;
Δ = b2-4ac
Δ = 72-4·3·4
Δ = 1
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1}=1$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(7)-1}{2*3}=\frac{-8}{6}
=-1+1/3
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(7)+1}{2*3}=\frac{-6}{6}
=-1
$